What is expand 1/((x+3)(x+1)(x-5)) ?

The solution to expand 1/((x+3)(x+1)(x-5)) is 1/(x^3-x^2-17x-15)

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expand 1/((x+3)(x+1)(x-5))

expand

\frac{1}{( x + 3 ) ( x + 1 ) ( x - 5 )}

\frac{1}{x ^{3} - x ^{2} - 17 x - 15}

Solution steps

\frac{1}{( x + 3 ) ( x + 1 ) ( x - 5 )}

Expand

(x + 3) (x + 1) (x - 5) : x^{3} - x^{2} - 17 x - 15

= \frac{1}{x ^{3} - x ^{2} - 17 x - 15}

(- x + y + z = 3) \cdot (- 2)

(e - 2 x + 4) d y

\frac{1}{( x + 6 ) ^{4}}

(2 x + 3) (4 x + 4Δ x - 5)

\frac{5 ( s + 2 )}{s ^{2} ( s + 1 ) ( s + 5 )}

What is expand 1/((x+3)(x+1)(x-5)) ?
The solution to expand 1/((x+3)(x+1)(x-5)) is 1/(x^3-x^2-17x-15)