What is expand (-2x^2+4x-1)/(x(x-1)) ?

The solution to expand (-2x^2+4x-1)/(x(x-1)) is (-2x^2+4x-1)/(x^2-x)

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expand (-2x^2+4x-1)/(x(x-1))

expand

\frac{- 2 x ^{2} + 4 x - 1}{x ( x - 1 )}

\frac{- 2 x ^{2} + 4 x - 1}{x ^{2} - x}

Solution steps

\frac{- 2 x ^{2} + 4 x - 1}{x ( x - 1 )}

Expand

x (x - 1) : x^{2} - x

= \frac{- 2 x ^{2} + 4 x - 1}{x ^{2} - x}

\frac{x + 6}{( s + 4 ) ( s + 1 )}

\frac{1}{( ( x + h ) + 4 ) ^{2}}

- (7 (2 - 2)^{6} (1 - 0) + c = 0)

ab (a + b) - b c (b + e) + a c (a - e)

e^{i (a + b)}

What is expand (-2x^2+4x-1)/(x(x-1)) ?
The solution to expand (-2x^2+4x-1)/(x(x-1)) is (-2x^2+4x-1)/(x^2-x)