What is expand ((x-2)(x-3))/(12) ?

The solution to expand ((x-2)(x-3))/(12) is (x^2)/(12)-(5x)/(12)+1/2

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expand ((x-2)(x-3))/(12)

expand

\frac{( x - 2 ) ( x - 3 )}{12}

\frac{x ^{2}}{12} - \frac{5 x}{12} + \frac{1}{2}

Solution steps

\frac{( x - 2 ) ( x - 3 )}{12}

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

= \frac{x ^{2} - 5 x + 6}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 5 x + 6}{12} = \frac{x ^{2}}{12} - \frac{5 x}{12} + \frac{6}{12}

= \frac{x ^{2}}{12} - \frac{5 x}{12} + \frac{6}{12}

Cancel

\frac{6}{12} : \frac{1}{2}

= \frac{x ^{2}}{12} - \frac{5 x}{12} + \frac{1}{2}

(- 2, 4) y (3, - 3)

\frac{1}{( x + 3 ) ^{3}}

\frac{( 8 x - 3 ) ^{2}}{64}

\frac{3 ( 2 - x )}{x}

8 x y (3 x - y = 2 z)

What is expand ((x-2)(x-3))/(12) ?
The solution to expand ((x-2)(x-3))/(12) is (x^2)/(12)-(5x)/(12)+1/2