What is expand ((x+2)(x-1))/((x-2)(x+1)) ?

The solution to expand ((x+2)(x-1))/((x-2)(x+1)) is (x^2+x-2)/(x^2-x-2)

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expand ((x+2)(x-1))/((x-2)(x+1))

expand

\frac{( x + 2 ) ( x - 1 )}{( x - 2 ) ( x + 1 )}

\frac{x ^{2} + x - 2}{x ^{2} - x - 2}

Solution steps

\frac{( x + 2 ) ( x - 1 )}{( x - 2 ) ( x + 1 )}

Expand

(x - 2) (x + 1) : x^{2} - x - 2

= \frac{( x + 2 ) ( x - 1 )}{x ^{2} - x - 2}

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \frac{x ^{2} + x - 2}{x ^{2} - x - 2}

\frac{4 x ( y ^{2} - 4 )}{x ^{2} + 2}

3 \frac{d}{d x} ((x - 3)^{2} x^{2})

\frac{( x + 8 ) ( x + 2 )}{x + 5}

(6 - 3 e^{- x})^{2}

8 x^{3} y d x + (2 y^{4} - 9 x^{4}) d y

What is expand ((x+2)(x-1))/((x-2)(x+1)) ?
The solution to expand ((x+2)(x-1))/((x-2)(x+1)) is (x^2+x-2)/(x^2-x-2)