What is expand (x+3)/((x-7)(x+2)) ?

The solution to expand (x+3)/((x-7)(x+2)) is (x+3)/(x^2-5x-14)

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expand (x+3)/((x-7)(x+2))

expand

\frac{x + 3}{( x - 7 ) ( x + 2 )}

\frac{x + 3}{x ^{2} - 5 x - 14}

Solution steps

\frac{x + 3}{( x - 7 ) ( x + 2 )}

Expand

(x - 7) (x + 2) : x^{2} - 5 x - 14

= \frac{x + 3}{x ^{2} - 5 x - 14}

\frac{π ( e ^{7} - 1 )}{7 e ^{7}}

\frac{d}{d t} ((X) (X - 1) (1 - 2 X))

(X + Y) (X + Y^{^{'}})

(e^{x} - e^{- x})^{5}

\frac{( x ^{2} + 1 ) ^{3}}{6}

What is expand (x+3)/((x-7)(x+2)) ?
The solution to expand (x+3)/((x-7)(x+2)) is (x+3)/(x^2-5x-14)