What are the solutions to the equation 3x^2-18x=120 ?

The solutions to the equation 3x^2-18x=120 are x=10,x=-4

Find the zeros of 3x^2-18x=120

The zeros of 3x^2-18x=120 are x=10,x=-4

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3 x^{2} - 18 x = 120

x = 10, x = - 4

Solution steps

3 x^{2} - 18 x = 120

Move

120

to the left side

3 x^{2} - 18 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 ( - 120 )}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 (- 120) = 42

x_{1, 2} = \frac{- ( - 18 ) \pm 42}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 42}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 42}{2 \cdot 3}

x = \frac{- ( - 18 ) + 42}{2 \cdot 3} : 10

x = \frac{- ( - 18 ) - 42}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = 10, x = - 4

2 x^{2} = 2 x - 3

- x < - 2 or 5 x + 1 < - 13

x^{3} - 3 x^{2} - 4 x + 12

- x^{2} + 2 x + 24

What are the solutions to the equation 3x^2-18x=120 ?
The solutions to the equation 3x^2-18x=120 are x=10,x=-4
Find the zeros of 3x^2-18x=120
The zeros of 3x^2-18x=120 are x=10,x=-4