What is expand (e^x-e^{-x})(e^x) ?

The solution to expand (e^x-e^{-x})(e^x) is e^{2x}-1

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expand (e^x-e^{-x})(e^x)

expand

(e^{x} - e^{- x}) (e^{x})

e^{2 x} - 1

Solution steps

(e^{x} - e^{- x}) (e^{x})

= (e^{x}) (e^{x} - e^{- x})

Apply the distributive law:

a (b - c) = ab - a c

a = (e^{x}), b = e^{x}, c = e^{- x}

= (e^{x}) e^{x} - (e^{x}) e^{- x}

= e^{x} (e^{x}) - e^{- x} (e^{x})

Simplify

e^{x} (e^{x}) - e^{- x} (e^{x}) : e^{2 x} - 1

= e^{2 x} - 1

e^{t} (1 + e^{- 2 t})

f (x + d x, y, z) - f (x, y, z)

\frac{( x ^{2} - 1 ) ( x + 2 )}{x}

\frac{d}{d t} ((t) (k (t - M)))

(3 x + y - 2 z)^{5}

What is expand (e^x-e^{-x})(e^x) ?
The solution to expand (e^x-e^{-x})(e^x) is e^{2x}-1