What is expand (2x+8)/((x+1)(x-1)) ?

The solution to expand (2x+8)/((x+1)(x-1)) is (2x+8)/(x^2-1)

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expand (2x+8)/((x+1)(x-1))

expand

\frac{2 x + 8}{( x + 1 ) ( x - 1 )}

\frac{2 x + 8}{x ^{2} - 1}

Solution steps

\frac{2 x + 8}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{2 x + 8}{x ^{2} - 1}

(ln (x) + 1) (2)

\frac{x ^{2} - x + 3}{( x - 2 ) ^{3}}

4 a^{2} - 2 (2 b)^{3} + ab (a = - 1, b = 2)

\frac{( 2 a + 1 ) ^{2}}{4}

a^{(2 n + 1) (2 n - 1)}

What is expand (2x+8)/((x+1)(x-1)) ?
The solution to expand (2x+8)/((x+1)(x-1)) is (2x+8)/(x^2-1)