What is expand p^1(-2,-3) ?

The solution to expand p^1(-2,-3) is -2p^1,-3p^1

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expand p^1(-2,-3)

expand

p^{1} (- 2, - 3)

- 2 p^{1}, - 3 p^{1}

Solution steps

p^{1} (- 2, - 3)

= (- 2, - 3) p^{1}

Apply the distributive law:

a (b - c) = ab - a c

a = p^{1}, b = - 2,, c = 3

= p^{1} (- 2,) - p^{1} \cdot 3

Apply minus-plus rules

+ (- a) = - a

= - 2 p^{1}, - 3 p^{1}

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