What is the answer to (x-3)^2=(x+3)^2+60 ?

The answer to (x-3)^2=(x+3)^2+60 is x=-5

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(x-3)^2=(x+3)^2+60

(x - 3)^{2} = (x + 3)^{2} + 60

x = - 5

Solution steps

(x - 3)^{2} = (x + 3)^{2} + 60

Expand

(x - 3)^{2} : x^{2} - 6 x + 9

Expand

(x + 3)^{2} + 60 : x^{2} + 6 x + 69

x^{2} - 6 x + 9 = x^{2} + 6 x + 69

Move

9

to the right side

x^{2} - 6 x = x^{2} + 6 x + 60

Subtract

x^{2} + 6 x

from both sides

x^{2} - 6 x - (x^{2} + 6 x) = x^{2} + 6 x + 60 - (x^{2} + 6 x)

Simplify

- 12 x = 60

Divide both sides by

- 12

x = - 5

x + 1 = x^{2} - 19 x - 20

x^{100} - 1

\frac{2 ^{2}}{2 !}

9 x^{2} + 30 x + 25 = 11

3 \cdot 2 - 2 y = 6

What is the answer to (x-3)^2=(x+3)^2+60 ?
The answer to (x-3)^2=(x+3)^2+60 is x=-5
Solve for x: (x-3)^2=(x+3)^2+60
The solution is x=-5