What is expand α(cα,aα+bα+cα,4aα+2bα+cα) ?

The solution to expand α(cα,aα+bα+cα,4aα+2bα+cα) is ααc,αa+ααb+ααc,4αa+2ααb+ααc

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expand α(cα,aα+bα+cα,4aα+2bα+cα)

expand

α (c α, a α + b α + c α, 4 a α + 2 b α + c α)

αα c, α a + αα b + αα c, 4 α a + 2 αα b + αα c

Solution steps

α (c α, a α + b α + c α, 4 a α + 2 b α + c α)

= α (, αα c a + α b + 4, αα c a + 2 α b + α c)

Distribute parentheses

= α c α, a α + α b α + α c α, 4 a α + α \cdot 2 b α + α c α

= αα c, α a + αα b + αα c, 4 α a + 2 αα b + αα c

- \frac{8 s + 25}{( s + 4 ) ^{2}}

(1 + j) e^{\frac{jπ t}{2}}

(p + t) (e + t)

\frac{100 ( s + 25 )}{s ( s + 5 ) ^{3}}

y (1 + x y) d x + (2 y - x) d y

What is expand α(cα,aα+bα+cα,4aα+2bα+cα) ?
The solution to expand α(cα,aα+bα+cα,4aα+2bα+cα) is ααc,αa+ααb+ααc,4αa+2ααb+ααc