What is expand (1+x^2)y'(x)+4xy ?

The solution to expand (1+x^2)y'(x)+4xy is y'(x)+x^2y'(x)+4xy

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expand (1+x^2)y'(x)+4xy

expand

(1 + x^{2}) y^{'} (x) + 4 x y

y' (x) + x^{2} y' (x) + 4 x y

Solution steps

(1 + x^{2}) y^{'} (x) + 4 x y

Expand

y^{'} (x) (1 + x^{2}) : y^{'} (x) + x^{2} y^{'} (x)

= y^{'} (x) + x^{2} y^{'} (x) + 4 x y

\frac{3 ( 1 - y ) ^{2}}{2}

\frac{n ( 2 n + 1 ) ( 4 n + 1 )}{3}

(4 x^{2} - y^{2}) d x

(f \circ g) (2 - 8 x) (x^{3})

\frac{5}{s ( s ^{2} + 5 s + 50 )}

What is expand (1+x^2)y'(x)+4xy ?
The solution to expand (1+x^2)y'(x)+4xy is y'(x)+x^2y'(x)+4xy