What is expand 3(2s-2/3 =6s-z) ?

The solution to expand 3(2s-2/3 =6s-z) is 6s-2=6s-3z

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expand 3(2s-2/3 =6s-z)

expand

3 (2 s - \frac{2}{3} = 6 s - z)

6 s - 2 = 6 s - 3 z

Solution steps

3 (2 s - \frac{2}{3} = 6 s - z)

= 3 (2 s - 6 \cdot \frac{2}{3} = s - z)

Distribute parentheses

= 3 \cdot 2 s + 3 (- \frac{2}{3} = 6 s) + 3 (- z)

Apply minus-plus rules

+ (- a) = - a

3 \cdot 2 s - 3 \cdot \frac{2}{3} = 6 s - 3 z

Expand

3 \cdot 2 s - 3 \cdot \frac{2}{3} : 6 s - 2

6 s - 2 = 6 s - 3 z

\frac{x \cdot ( x + 2 )}{2}

\frac{2 x - 10}{( x + 1 ) ( x - 3 )}

\frac{1}{s ^{2} ( s ^{2} + 2 s + 5 )}

e^{2 (l n ∣ x ∣ + C)}

\frac{1}{( x + 1 ) ^{3} ( 2 x - 1 ) ^{3}}

What is expand 3(2s-2/3 =6s-z) ?
The solution to expand 3(2s-2/3 =6s-z) is 6s-2=6s-3z