What is expand 4(y^2-1)dx+3(x^2-4)dy ?

The solution to expand 4(y^2-1)dx+3(x^2-4)dy is 4y^2dx-4dx+3x^2dy-12dy

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expand 4(y^2-1)dx+3(x^2-4)dy

expand

4 (y^{2} - 1) d x + 3 (x^{2} - 4) d y

4 y^{2} d x - 4 d x + 3 x^{2} d y - 12 d y

Solution steps

4 (y^{2} - 1) d x + 3 (x^{2} - 4) d y

Expand

4 d x (y^{2} - 1) : 4 y^{2} d x - 4 d x

= 4 y^{2} d x - 4 d x + 3 (x^{2} - 4) d y

Expand

3 d y (x^{2} - 4) : 3 x^{2} d y - 12 d y

= 4 y^{2} d x - 4 d x + 3 x^{2} d y - 12 d y

sin ((x + y) \cdot sin (x - y))

(8 x - 9 y = 1, 2) - (- 20 x + 3 y = 48)

(3 x + vx) v d x + x d v

3 - 3 (1 = 2 + 6 (3 - \frac{5}{6} t))

x (x + 1 = 0)

What is expand 4(y^2-1)dx+3(x^2-4)dy ?
The solution to expand 4(y^2-1)dx+3(x^2-4)dy is 4y^2dx-4dx+3x^2dy-12dy