What is expand 1/((x-1)(x^2+9)) ?

The solution to expand 1/((x-1)(x^2+9)) is 1/(x^3+9x-x^2-9)

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expand 1/((x-1)(x^2+9))

expand

\frac{1}{( x - 1 ) ( x ^{2} + 9 )}

\frac{1}{x ^{3} + 9 x - x ^{2} - 9}

Solution steps

\frac{1}{( x - 1 ) ( x ^{2} + 9 )}

Expand

(x - 1) (x^{2} + 9) : x^{3} + 9 x - x^{2} - 9

= \frac{1}{x ^{3} + 9 x - x ^{2} - 9}

\frac{( x - 1 ) ( x - 3 )}{x + 2}

e^{- x} - e^{- x} (x + c) + (x + c) e^{x}

cos (v) (v d y + y d v) + (y d y + v y d y)

\frac{1}{5 ( 10 x + 25 )}

(x - \frac{π}{4})^{3}

What is expand 1/((x-1)(x^2+9)) ?
The solution to expand 1/((x-1)(x^2+9)) is 1/(x^3+9x-x^2-9)