What is expand-(x(-x+3)^3)/(27) ?

The solution to expand-(x(-x+3)^3)/(27) is (x^4}{27}-\frac{x^3)/3+x^2-x

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expand-(x(-x+3)^3)/(27)

expand

- \frac{x ( - x + 3 ) ^{3}}{27}

\frac{x ^{4}}{27} - \frac{x ^{3}}{3} + x^{2} - x

Solution steps

- \frac{x ( - x + 3 ) ^{3}}{27}

(- x + 3)^{3} = - x^{3} + 9 x^{2} - 27 x + 27

= - \frac{x ( - x ^{3} + 9 x ^{2} - 27 x + 27 )}{27}

Expand

x (- x^{3} + 9 x^{2} - 27 x + 27) : - x^{4} + 9 x^{3} - 27 x^{2} + 27 x

= - \frac{- x ^{4} + 9 x ^{3} - 27 x ^{2} + 27 x}{27}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- x ^{4} + 9 x ^{3} - 27 x ^{2} + 27 x}{27} = - (- \frac{x ^{4}}{27}) - (\frac{9 x ^{3}}{27}) - (- \frac{27 x ^{2}}{27}) - (\frac{27 x}{27})

= - (- \frac{x ^{4}}{27}) - (\frac{9 x ^{3}}{27}) - (- \frac{27 x ^{2}}{27}) - (\frac{27 x}{27})

Remove parentheses:

(a) = a, - (- a) = a

= \frac{x ^{4}}{27} - \frac{9 x ^{3}}{27} + \frac{27 x ^{2}}{27} - \frac{27 x}{27}

Cancel

\frac{9 x ^{3}}{27} : \frac{x ^{3}}{3}

= \frac{x ^{4}}{27} - \frac{x ^{3}}{3} + \frac{27 x ^{2}}{27} - \frac{27 x}{27}

Divide the numbers:

\frac{27}{27} = 1

= \frac{x ^{4}}{27} - \frac{x ^{3}}{3} + x^{2} - x

(y + y) 2 π

\frac{4 ( b + 2 )}{3}

\frac{- y ^{2} - 6 x y}{x ( 2 y + 3 x )}

(\frac{23 + 2 x}{5})^{2}

\frac{( a ^{2} )}{s ^{2} ( s + a )}

What is expand-(x(-x+3)^3)/(27) ?
The solution to expand-(x(-x+3)^3)/(27) is (x^4}{27}-\frac{x^3)/3+x^2-x