What is expand (3z+3)(3z-3)' ?

The solution to expand (3z+3)(3z-3)' is 3z(3z-3)'+3(3z-3)'

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expand (3z+3)(3z-3)'

expand

(3 z + 3) (3 z - 3)^{'}

3 z (3 z - 3)' + 3 (3 z - 3)'

Solution steps

(3 z + 3) (3 z - 3)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (3 z - 3)^{'}, b = 3 z, c = 3

= (3 z - 3)^{^{'}} 3 z + (3 z - 3)^{^{'}} 3

= 3 z (3 z - 3)^{^{'}} + 3 (3 z - 3)^{^{'}}

π 2 (1 + \frac{π ^{2}}{3})

(3 x^{2} y + 3 y) d y - 3 x d x

y (x + 1) + y^{'} (x)

(x^{2} + 4 x - 2)^{9}

\frac{( 2 x + 5 ) ^{4}}{8}

What is expand (3z+3)(3z-3)' ?
The solution to expand (3z+3)(3z-3)' is 3z(3z-3)'+3(3z-3)'