What is expand (4n^2+2n-1)(2n-1)! ?

The solution to expand (4n^2+2n-1)(2n-1)! is 4n^2(2n-1)!+2n(2n-1)!-(2n-1)!

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expand (4n^2+2n-1)(2n-1)!

expand

(4 n^{2} + 2 n - 1) (2 n - 1)!

4 n^{2} (2 n - 1)! + 2 n (2 n - 1)! - (2 n - 1)!

Solution steps

(4 n^{2} + 2 n - 1) (2 n - 1)!

= (2 n - 1)! (4 n^{2} + 2 n - 1)

Distribute parentheses

= (2 n - 1)! \cdot 4 n^{2} + (2 n - 1)! \cdot 2 n + (2 n - 1)! (- 1)

Apply minus-plus rules

+ (- a) = - a

= 4 n^{2} (2 n - 1)! + 2 n (2 n - 1)! - 1 \cdot (2 n - 1)!

Multiply:

1 \cdot (2 n - 1)! = (2 n - 1)!

= 4 n^{2} (2 n - 1)! + 2 n (2 n - 1)! - (2 n - 1)!

(- 7, - 5, 18) (y)

A (- 2, 3) y B (5, - 4)

\frac{d}{d x} ((2 - x) e^{x}) - x - 2

(1 + c e^{x})^{2}

- 2 sin (2 (x - 45)) + 1

What is expand (4n^2+2n-1)(2n-1)! ?
The solution to expand (4n^2+2n-1)(2n-1)! is 4n^2(2n-1)!+2n(2n-1)!-(2n-1)!