What are the solutions to the equation 3y^2-18y=0 ?

The solutions to the equation 3y^2-18y=0 are y=6,y=0

Find the zeros of 3y^2-18y=0

The zeros of 3y^2-18y=0 are y=6,y=0

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3 y^{2} - 18 y = 0

y = 6, y = 0

Solution steps

3 y^{2} - 18 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 0 = 18

y_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 18 ) + 18}{2 \cdot 3}, y_{2} = \frac{- ( - 18 ) - 18}{2 \cdot 3}

y = \frac{- ( - 18 ) + 18}{2 \cdot 3} : 6

y = \frac{- ( - 18 ) - 18}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

y = 6, y = 0

16 x^{2} - 16 x - 5

9 x^{2} + 36 x + 11

8 y = 48

- 4 x^{2} + 8 x - 7 = 0

- 3 (2 n - 11) > n + 26

What are the solutions to the equation 3y^2-18y=0 ?
The solutions to the equation 3y^2-18y=0 are y=6,y=0
Find the zeros of 3y^2-18y=0
The zeros of 3y^2-18y=0 are y=6,y=0