What is expand (x-3(2y-z))/(2xy) ?

The solution to expand (x-3(2y-z))/(2xy) is 1/(2y)-3/x+(3z)/(2xy)

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expand (x-3(2y-z))/(2xy)

expand

\frac{x - 3 ( 2 y - z )}{2 x y}

\frac{1}{2 y} - \frac{3}{x} + \frac{3 z}{2 x y}

Solution steps

\frac{x - 3 ( 2 y - z )}{2 x y}

Expand

x - 3 (2 y - z) : x - 6 y + 3 z

= \frac{x - 6 y + 3 z}{2 x y}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x - 6 y + 3 z}{2 x y} = \frac{x}{2 x y} - \frac{6 y}{2 x y} + \frac{3 z}{2 x y}

= \frac{x}{2 x y} - \frac{6 y}{2 x y} + \frac{3 z}{2 x y}

Cancel

\frac{x}{2 x y} : \frac{1}{2 y}

= \frac{1}{2 y} - \frac{6 y}{2 x y} + \frac{3 z}{2 x y}

Cancel

\frac{6 y}{2 x y} : \frac{3}{x}

= \frac{1}{2 y} - \frac{3}{x} + \frac{3 z}{2 x y}

3 (2 z - 10 = - 12)

cos (2) (x + \frac{π}{8})

\frac{( s + 1 ) ( 2 s + 1 )}{s}

\frac{1 - x ^{2}}{x ^{3} ( x ^{2} + 7 )}

\frac{mn}{r ( 2 m + 1 )}

What is expand (x-3(2y-z))/(2xy) ?
The solution to expand (x-3(2y-z))/(2xy) is 1/(2y)-3/x+(3z)/(2xy)