What is expand-0.25(1-x)ln(1-x) ?

The solution to expand-0.25(1-x)ln(1-x) is -0.25ln(1-x)+0.25xln(1-x)

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expand-0.25(1-x)ln(1-x)

expand

- 0.25 (1 - x) ln (1 - x)

- 0.25 ln (1 - x) + 0.25 x ln (1 - x)

Solution steps

- 0.25 (1 - x) ln (1 - x)

= - 0.25 ln (1 - x) (1 - x)

Apply the distributive law:

a (b - c) = ab - a c

a = - 0.25 ln (1 - x), b = 1, c = x

= - 0.25 ln (1 - x) \cdot 1 - (- 0.25 ln (1 - x)) x

Apply minus-plus rules

- (- a) = a

= - 1 \cdot 0.25 ln (1 - x) + 0.25 x ln (1 - x)

Multiply the numbers:

1 \cdot 0.25 = 0.25

= - 0.25 ln (1 - x) + 0.25 x ln (1 - x)

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What is expand-0.25(1-x)ln(1-x) ?
The solution to expand-0.25(1-x)ln(1-x) is -0.25ln(1-x)+0.25xln(1-x)