What is expand (3c-4e-2b)(-3c-4d+b) ?

The solution to expand (3c-4e-2b)(-3c-4d+b) is -9c^2+12ec+9cb-12cd-2b^2-4eb+16ed+8bd

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expand (3c-4e-2b)(-3c-4d+b)

expand

(3 c - 4 e - 2 b) (- 3 c - 4 d + b)

- 9 c^{2} + 12 ec + 9 c b - 12 c d - 2 b^{2} - 4 e b + 16 e d + 8 b d

Solution steps

(3 c - 4 e - 2 b) (- 3 c - 4 d + b)

Distribute parentheses

= 3 c (- 3 c) + 3 c (- 4 d) + 3 c b + (- 4 e) (- 3 c) + (- 4 e) (- 4 d) + (- 4 e) b + (- 2 b) (- 3 c) + (- 2 b) (- 4 d) + (- 2 b) b

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= - 3 \cdot 3 cc - 3 \cdot 4 c d + 3 c b + 4 \cdot 3 ec + 4 \cdot 4 e d - 4 e b + 2 \cdot 3 c b + 2 \cdot 4 b d - 2 bb

Simplify

- 3 \cdot 3 cc - 3 \cdot 4 c d + 3 c b + 4 \cdot 3 ec + 4 \cdot 4 e d - 4 e b + 2 \cdot 3 c b + 2 \cdot 4 b d - 2 bb : - 9 c^{2} + 12 ec + 9 c b - 12 c d - 2 b^{2} - 4 e b + 16 e d + 8 b d

= - 9 c^{2} + 12 ec + 9 c b - 12 c d - 2 b^{2} - 4 e b + 16 e d + 8 b d

sec (a) (2, - 1)

(2 x^{2} - 5) e^{x^{2}}

\frac{e ^{- 3 s}}{s ^{2} ( s ^{2} + 4 )}

\frac{1}{( j w + 0.05 ) ( j w + 2 )}

(2 (1 + i))^{\frac{1}{2}}

What is expand (3c-4e-2b)(-3c-4d+b) ?
The solution to expand (3c-4e-2b)(-3c-4d+b) is -9c^2+12ec+9cb-12cd-2b^2-4eb+16ed+8bd