What is expand 3(2e^{3t}-e^{2t}) ?

The solution to expand 3(2e^{3t}-e^{2t}) is 6e^{3t}-3e^{2t}

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expand 3(2e^{3t}-e^{2t})

expand

3 (2 e^{3 t} - e^{2 t})

6 e^{3 t} - 3 e^{2 t}

Solution steps

3 (2 e^{3 t} - e^{2 t})

Apply the distributive law:

a (b - c) = ab - a c

a = 3, b = 2 e^{3 t}, c = e^{2 t}

= 3 \cdot 2 e^{3 t} - 3 e^{2 t}

Multiply the numbers:

3 \cdot 2 = 6

= 6 e^{3 t} - 3 e^{2 t}

\frac{5 ( - a + 5 )}{13}

1 + 2 i

\frac{1}{( x - 3 ) ( x + h - 3 )}

(3 x^{2} + x + 1) e^{x} ln (x)

2 (3 x + 2 y = 8)

What is expand 3(2e^{3t}-e^{2t}) ?
The solution to expand 3(2e^{3t}-e^{2t}) is 6e^{3t}-3e^{2t}