What is expand (2x-1)*(ln(5)) ?

The solution to expand (2x-1)*(ln(5)) is 2ln(5)x-ln(5)

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expand (2x-1)*(ln(5))

expand

(2 x - 1) \cdot (ln (5))

2 ln (5) x - ln (5)

Solution steps

(2 x - 1) (ln (5))

= (ln (5)) (2 x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = (ln (5)), b = 2 x, c = 1

= (ln (5)) \cdot 2 x - (ln (5)) \cdot 1

= 2 (ln (5)) x - 1 \cdot (ln (5))

Simplify

2 (ln (5)) x - 1 \cdot (ln (5)) : 2 ln (5) x - ln (5)

= 2 ln (5) x - ln (5)

(x + d x - 1)^{2}

\frac{d}{d x} ((c) (3 x^{2} + 60))

(x - 8) d x - d y

9 u sin (\frac{π}{2} (t + 1))

\frac{3 X - 1}{X ( 3 X + 1 )}

What is expand (2x-1)*(ln(5)) ?
The solution to expand (2x-1)*(ln(5)) is 2ln(5)x-ln(5)