What are the solutions to the equation 4x^2+32x+64=0 ?

The solutions to the equation 4x^2+32x+64=0 are x=-4

Find the zeros of 4x^2+32x+64=0

The zeros of 4x^2+32x+64=0 are x=-4

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4 x^{2} + 32 x + 64 = 0

x = - 4

Solution steps

4 x^{2} + 32 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 4 \cdot 64}{2 \cdot 4}

3 2^{2} - 4 \cdot 4 \cdot 64 = 0

x_{1, 2} = \frac{- 32 \pm 0}{2 \cdot 4}

x = \frac{- 32}{2 \cdot 4}

\frac{- 32}{2 \cdot 4} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

6 x - 2 x + 11 = - 5

x^{2} + 2 x + 33 = 0

- 2 y > 4

3 x^{2} + 10 + 8

\frac{3 x - 1}{4} = - 5

What are the solutions to the equation 4x^2+32x+64=0 ?
The solutions to the equation 4x^2+32x+64=0 are x=-4
Find the zeros of 4x^2+32x+64=0
The zeros of 4x^2+32x+64=0 are x=-4