What is expand (2x^2-8)/((x^2+4)^2) ?

The solution to expand (2x^2-8)/((x^2+4)^2) is (2x^2-8)/(x^4+8x^2+16)

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expand (2x^2-8)/((x^2+4)^2)

expand

\frac{2 x ^{2} - 8}{( x ^{2} + 4 ) ^{2}}

\frac{2 x ^{2} - 8}{x ^{4} + 8 x ^{2} + 16}

Solution steps

\frac{2 x ^{2} - 8}{( x ^{2} + 4 ) ^{2}}

(x^{2} + 4)^{2} = x^{4} + 8 x^{2} + 16

= \frac{2 x ^{2} - 8}{x ^{4} + 8 x ^{2} + 16}

3 (x^{7} = 5 (x - 1) - 4 x)

\frac{x + 1}{( x + 3 ) ^{2}}

\frac{( 2 x + 5 ) x}{4}

(3 x^{2} + y^{2}) d x + 2 x y d y

(3 x + 2 y + 1)^{5}

What is expand (2x^2-8)/((x^2+4)^2) ?
The solution to expand (2x^2-8)/((x^2+4)^2) is (2x^2-8)/(x^4+8x^2+16)