What is expand pi((2n+1)-pi/2) ?

The solution to expand pi((2n+1)-pi/2) is 2pin+pi-(pi^2)/2

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expand pi((2n+1)-pi/2)

expand

π ((2 n + 1) - \frac{π}{2})

2 πn + π - \frac{π ^{2}}{2}

Solution steps

π ((2 n + 1) - \frac{π}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = π, b = (2 n + 1), c = \frac{π}{2}

= π (2 n + 1) - π \frac{π}{2}

Simplify

π (2 n + 1) - π \frac{π}{2} : 2 πn + π - \frac{π ^{2}}{2}

= 2 πn + π - \frac{π ^{2}}{2}

a (e^{2} p q^{2} b^{2} - c)

2 π (k + \frac{k}{5})

(A + B \cdot t) \cdot e^{t}

\frac{1}{x ( 1 - x ) ^{2}}

y - 2 \pm \frac{4}{3} (x + 3)

What is expand pi((2n+1)-pi/2) ?
The solution to expand pi((2n+1)-pi/2) is 2pin+pi-(pi^2)/2