What is expand (x-1)(x^2+x+1)' ?

The solution to expand (x-1)(x^2+x+1)' is x(x^2+x+1)'-(x^2+x+1)'

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expand (x-1)(x^2+x+1)'

expand

(x - 1) (x^{2} + x + 1)^{'}

x (x^{2} + x + 1)' - (x^{2} + x + 1)'

Solution steps

(x - 1) (x^{2} + x + 1)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (x^{2} + x + 1)^{'}, b = x, c = 1

= (x^{2} + x + 1)^{^{'}} x - (x^{2} + x + 1)^{^{'}} 1

= x (x^{2} + x + 1)^{^{'}} - 1 (x^{2} + x + 1)^{^{'}}

Multiply:

1 (x^{2} + x + 1)^{'} = (x^{2} + x + 1)^{'}

= x (x^{2} + x + 1)^{^{'}} - (x^{2} + x + 1)^{^{'}}

\frac{( x + 2 ) ^{2}}{( x - 1 ) ^{3}}

(2 x - y) d x + (x + 3 y) d y

\frac{1}{( 1 - x ) ^{2}}

x (\frac{x}{2} - 8 = y)

\frac{( 3 x - 9 ) ^{2}}{16}

What is expand (x-1)(x^2+x+1)' ?
The solution to expand (x-1)(x^2+x+1)' is x(x^2+x+1)'-(x^2+x+1)'