What is expand ((n+1)(n-1)!)/n ?

The solution to expand ((n+1)(n-1)!)/n is (n-1)!+((n-1)!)/n

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expand ((n+1)(n-1)!)/n

expand

\frac{( n + 1 ) ( n - 1 ) !}{n}

(n - 1)! + \frac{( n - 1 ) !}{n}

Solution steps

\frac{( n + 1 ) ( n - 1 ) !}{n}

Expand

(n + 1) (n - 1)! : n (n - 1)! + (n - 1)!

= \frac{n ( n - 1 ) ! + ( n - 1 ) !}{n}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ( n - 1 ) ! + ( n - 1 ) !}{n} = \frac{n ( n - 1 ) !}{n} + \frac{( n - 1 ) !}{n}

= \frac{n ( n - 1 ) !}{n} + \frac{( n - 1 ) !}{n}

Cancel

\frac{n ( n - 1 ) !}{n} : (n - 1)!

= (n - 1)! + \frac{( n - 1 ) !}{n}

9 cos (2 (x + 6^{\circ})) - 5

(x y = 1, 2) (x^{2} - 5 y^{2} = 16)

(x + Δ x)^{4}

\frac{18 x + 30}{x ( x ^{2} + 8 x + 25 )}

\frac{d}{d t} ((2 t + 1) t) + 1

What is expand ((n+1)(n-1)!)/n ?
The solution to expand ((n+1)(n-1)!)/n is (n-1)!+((n-1)!)/n