What is expand ,16(x-3)^2+8(x-3) ?

The solution to expand ,16(x-3)^2+8(x-3) is 16x^2-88x+120

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expand ,16(x-3)^2+8(x-3)

expand

16 (x - 3)^{2} + 8 (x - 3)

16 x^{2} - 88 x + 120

Solution steps

16 (x - 3)^{2} + 8 (x - 3)

Expand

16 (x - 3)^{2} : 16 x^{2} - 96 x + 144

= 16 x^{2} - 96 x + 144 + 8 (x - 3)

Expand

8 (x - 3) : 8 x - 24

= 16 x^{2} - 96 x + 144 + 8 x - 24

Simplify

16 x^{2} - 96 x + 144 + 8 x - 24 : 16 x^{2} - 88 x + 120

= 16 x^{2} - 88 x + 120

\frac{5 ( 2 x - 5 )}{3 ( 3 x + 2 )}

\frac{1}{( y - 2 ) ( y + 2 )}

7 (ln (8 x) + 1)

8^{5}

P (6, - 3) y Q (- 2, - 3) 7

What is expand ,16(x-3)^2+8(x-3) ?
The solution to expand ,16(x-3)^2+8(x-3) is 16x^2-88x+120