What is expand ((n-3)(n-4))/((n+3)^2) ?

The solution to expand ((n-3)(n-4))/((n+3)^2) is (n^2-7n+12)/(n^2+6n+9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((n-3)(n-4))/((n+3)^2)

expand

\frac{( n - 3 ) ( n - 4 )}{( n + 3 ) ^{2}}

\frac{n ^{2} - 7 n + 12}{n ^{2} + 6 n + 9}

Solution steps

\frac{( n - 3 ) ( n - 4 )}{( n + 3 ) ^{2}}

(n + 3)^{2} = n^{2} + 6 n + 9

= \frac{( n - 3 ) ( n - 4 )}{n ^{2} + 6 n + 9}

Expand

(n - 3) (n - 4) : n^{2} - 7 n + 12

= \frac{n ^{2} - 7 n + 12}{n ^{2} + 6 n + 9}

(5 x y + 4 y^{2} + 1) d x + (x^{2} + 2 x y) d y

\frac{( x ^{2} + 1 ) ^{2}}{x}

\frac{3 ( x ^{7} + 2 )}{x}

(y - 1) d y

\frac{( x + 5 ) ( x - 5 )}{2}

What is expand ((n-3)(n-4))/((n+3)^2) ?
The solution to expand ((n-3)(n-4))/((n+3)^2) is (n^2-7n+12)/(n^2+6n+9)