What is expand (-x+y=6,)(2x+y=3) ?

The solution to expand (-x+y=6,)(2x+y=3) is -2x^2-xy=3

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expand (-x+y=6,)(2x+y=3)

expand

(- x + y = 6,) (2 x + y = 3)

- 2 x^{2} - x y = 3

Solution steps

(- x + y = 6,) (2 x + y = 3)

= (- x + 6 =, y) (2 x + 3 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = - x, b = y = 6,, c = 2 x, d = y = 3

(- x) \cdot 2 x + (- x) y = 3 + y = 6, 2 x + y = 6, y = 3

Apply minus-plus rules

+ (- a) = - a

- 2 xx - x y = 3 + y = 6, 2 x + y = 6, y = 3

Expand

- 2 xx - x y : - 2 x^{2} - x y

- 2 x^{2} - x y = 3

ln (x - 1) \cdot (x - 1)

(- 3 x - 5 ux) (u d x + x d u)

\frac{( - 1 ) ^{x} + 3}{3 ^{x}}

(x - y - z)^{5}

\frac{t ^{n}}{e ^{(s - 3) t}}

What is expand (-x+y=6,)(2x+y=3) ?
The solution to expand (-x+y=6,)(2x+y=3) is -2x^2-xy=3