What is expand (7x+4y=1,3)(5x-2y=19) ?

The solution to expand (7x+4y=1,3)(5x-2y=19) is 35x^2-14xy=19

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expand (7x+4y=1,3)(5x-2y=19)

expand

(7 x + 4 y = 1, 3) (5 x - 2 y = 19)

35 x^{2} - 14 x y = 19

Solution steps

(7 x + 4 y = 1, 3) (5 x - 2 y = 19)

= (7 x + 4 \cdot 1 \cdot 3 =, y) (5 x - 2 \cdot 19 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 7 x, b = 4 y = 1, 3, c = 5 x, d = - 2 y = 19

7 x \cdot 5 x + 7 x (- 2 y = 19) + 4 y = 1, 3 \cdot 5 x + 4 y = 1, 3 (- 2 y = 19)

Apply minus-plus rules

+ (- a) = - a

7 \cdot 5 xx - 7 \cdot 2 x y = 19 + 4 y = 1, 3 \cdot 5 x - 4 y = 1, 3 \cdot 2 y = 19

Expand

7 \cdot 5 xx - 7 \cdot 2 x y : 35 x^{2} - 14 x y

35 x^{2} - 14 x y = 19

\frac{2}{x ( x - 2 )}

(a + h)^{2} - 1

49 + 15 - 5 (4) 2

\frac{9}{( s + 3 ) ^{2} s}

\frac{s + 1}{s ( s ^{2} + 9 )}

What is expand (7x+4y=1,3)(5x-2y=19) ?
The solution to expand (7x+4y=1,3)(5x-2y=19) is 35x^2-14xy=19