What are the solutions to the equation x^2+12x=x-24 ?

The solutions to the equation x^2+12x=x-24 are x=-3,x=-8

Find the zeros of x^2+12x=x-24

The zeros of x^2+12x=x-24 are x=-3,x=-8

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x^{2} + 12 x = x - 24

x = - 3, x = - 8

Solution steps

x^{2} + 12 x = x - 24

Move

24

to the left side

x^{2} + 12 x + 24 = x

Move

x

to the left side

x^{2} + 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 1}, x_{2} = \frac{- 11 - 5}{2 \cdot 1}

x = \frac{- 11 + 5}{2 \cdot 1} : - 3

x = \frac{- 11 - 5}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

\frac{a ^{3}}{a ^{2}}

11 (6 - w) + 8 = - 8 (w - 3) - 8

\frac{3}{4} x^{2} - \frac{1}{4} x = \frac{1}{2}

2 \cdot x + 12 = 40

lo g_{2} (2)

What are the solutions to the equation x^2+12x=x-24 ?
The solutions to the equation x^2+12x=x-24 are x=-3,x=-8
Find the zeros of x^2+12x=x-24
The zeros of x^2+12x=x-24 are x=-3,x=-8