What is expand 3/((x^2+9)(x^2+4)) ?

The solution to expand 3/((x^2+9)(x^2+4)) is 3/(x^4+13x^2+36)

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expand 3/((x^2+9)(x^2+4))

expand

\frac{3}{( x ^{2} + 9 ) ( x ^{2} + 4 )}

\frac{3}{x ^{4} + 13 x ^{2} + 36}

Solution steps

\frac{3}{( x ^{2} + 9 ) ( x ^{2} + 4 )}

Expand

(x^{2} + 9) (x^{2} + 4) : x^{4} + 13 x^{2} + 36

= \frac{3}{x ^{4} + 13 x ^{2} + 36}

\frac{2 x - 1}{( x - 1 ) ( x + 2 )}

P (- 2, 7, 3) Q (1, 2, - 2)

(2, - 1) y (\frac{- 13}{7})

\frac{24}{( x + 1 ) ^{5}}

(3 x - 2 y = 6) \frac{1}{6}

What is expand 3/((x^2+9)(x^2+4)) ?
The solution to expand 3/((x^2+9)(x^2+4)) is 3/(x^4+13x^2+36)