What is expand (1/(2a+b=-2,))(a-2b=8,) ?

The solution to expand (1/(2a+b=-2,))(a-2b=8,) is (1/(2a+=b-2,))a-2(1/(2a+=b-2,))b=8,

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expand (1/(2a+b=-2,))(a-2b=8,)

expand

(\frac{1}{2 a + b = - 2 ,}) (a - 2 b = 8,)

(\frac{1}{2 a + = b - 2 ,}) a - 2 (\frac{1}{2 a + = b - 2 ,}) b = 8,

Solution steps

(\frac{1}{2 a + b = - 2 ,}) (a - 2 b = 8,)

= (\frac{1}{2 a + = b - 2 ,}) (a - 2 \cdot 8 =, b)

Apply the distributive law:

a (b - c) = ab - a c

a = (\frac{1}{2 a + b = - 2 ,}), b = a, c = 2 b = 8,

(\frac{1}{2 a + b = - 2 ,}) a - (\frac{1}{2 a + b = - 2 ,}) \cdot 2 b = 8,

(\frac{1}{2 a + = b - 2 ,}) a - 2 (\frac{1}{2 a + = b - 2 ,}) b = 8,

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What is expand (1/(2a+b=-2,))(a-2b=8,) ?
The solution to expand (1/(2a+b=-2,))(a-2b=8,) is (1/(2a+=b-2,))a-2(1/(2a+=b-2,))b=8,