What is expand (2(Ls^2C+1))/(3sC) ?

The solution to expand (2(Ls^2C+1))/(3sC) is (2Ls)/3+2/(3sC)

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expand (2(Ls^2C+1))/(3sC)

expand

\frac{2 ( L s ^{2} C + 1 )}{3 s C}

\frac{2 L s}{3} + \frac{2}{3 s C}

Solution steps

\frac{2 ( L s ^{2} C + 1 )}{3 s C}

Expand

2 (L s^{2} C + 1) : 2 L s^{2} C + 2

= \frac{2 L s ^{2} C + 2}{3 s C}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 L s ^{2} C + 2}{3 s C} = \frac{2 L s ^{2} C}{3 s C} + \frac{2}{3 s C}

= \frac{2 L s ^{2} C}{3 s C} + \frac{2}{3 s C}

Cancel

\frac{2 L s ^{2} C}{3 s C} : \frac{2 L s}{3}

= \frac{2 L s}{3} + \frac{2}{3 s C}

\frac{6}{( x - 4 ) ^{3}}

(5 - 4 5^{\circ}) 5

v (24, - 3, 12, 0) y v (6, - 3, 5, - 4)

(\frac{1}{1 - 2 x})^{2}

(x, y) (x - 3 y + 4)

What is expand (2(Ls^2C+1))/(3sC) ?
The solution to expand (2(Ls^2C+1))/(3sC) is (2Ls)/3+2/(3sC)