What is expand f(x^2-9)\circ g(x^2+3x) ?

The solution to expand f(x^2-9)\circ g(x^2+3x) is \circ fx^4g+3\circ fx^3g-9\circ fx^2g-27\circ fxg

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expand f(x^2-9)\circ g(x^2+3x)

expand

f (x^{2} - 9) \circ g (x^{2} + 3 x)

\circ f x^{4} g + 3 \circ f x^{3} g - 9 \circ f x^{2} g - 27 \circ f xg

Solution steps

f (x^{2} - 9) \circ g (x^{2} + 3 x)

= \circ f g (x^{2} - 9) (x^{2} + 3 x)

Expand

(x^{2} - 9) (x^{2} + 3 x) : x^{4} + 3 x^{3} - 9 x^{2} - 27 x

= f \circ g (x^{4} + 3 x^{3} - 9 x^{2} - 27 x)

Expand

f \circ g (x^{4} + 3 x^{3} - 9 x^{2} - 27 x) : \circ f x^{4} g + 3 \circ f x^{3} g - 9 \circ f x^{2} g - 27 \circ f xg

= \circ f x^{4} g + 3 \circ f x^{3} g - 9 \circ f x^{2} g - 27 \circ f xg

(x^{2} y^{2} + x^{2} + y^{2} + 1) d y

\frac{a}{b} (2 x - 12 = \frac{c}{d})

\frac{3 π ( 2 + 2 )}{32}

(1 - e^{- 2 t})^{2}

\frac{2}{( x + 4 ) ^{2}}

What is expand f(x^2-9)\circ g(x^2+3x) ?
The solution to expand f(x^2-9)\circ g(x^2+3x) is \circ fx^4g+3\circ fx^3g-9\circ fx^2g-27\circ fxg