What is expand 1/((2+sin(θ))^4) ?

The solution to expand 1/((2+sin(θ))^4) is 1/(16+32sin(θ)+24sin^2(θ)+8sin^3(θ)+sin^4(θ))

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expand 1/((2+sin(θ))^4)

expand

\frac{1}{( 2 + sin ( θ ) ) ^{4}}

\frac{1}{16 + 32 sin ( θ ) + 24 sin ^{2} ( θ ) + 8 sin ^{3} ( θ ) + sin ^{4} ( θ )}

Solution steps

\frac{1}{( 2 + sin ( θ ) ) ^{4}}

(2 + sin (θ))^{4} = 16 + 32 sin (θ) + 24 sin^{2} (θ) + 8 sin^{3} (θ) + sin^{4} (θ)

= \frac{1}{16 + 32 sin ( θ ) + 24 sin ^{2} ( θ ) + 8 sin ^{3} ( θ ) + sin ^{4} ( θ )}

(1 - ln (x)) d x + (1 - ln (y)) d y

\frac{( 3 x ^{2} - x ) ^{3}}{3}

\frac{1}{s C ( L s + R ) + 1}

\frac{n ( 11 - n )}{2}

\frac{1}{x ( x - 1 ) ( x - 4 )}

What is expand 1/((2+sin(θ))^4) ?
The solution to expand 1/((2+sin(θ))^4) is 1/(16+32sin(θ)+24sin^2(θ)+8sin^3(θ)+sin^4(θ))