What is expand 7/((x^2-3x)^2) ?

The solution to expand 7/((x^2-3x)^2) is 7/(x^4-6x^3+9x^2)

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expand 7/((x^2-3x)^2)

expand

\frac{7}{( x ^{2} - 3 x ) ^{2}}

\frac{7}{x ^{4} - 6 x ^{3} + 9 x ^{2}}

Solution steps

\frac{7}{( x ^{2} - 3 x ) ^{2}}

(x^{2} - 3 x)^{2} = x^{4} - 6 x^{3} + 9 x^{2}

= \frac{7}{x ^{4} - 6 x ^{3} + 9 x ^{2}}

\frac{( x - 2 ) ^{2}}{36}

ro t a c i o na l (x^{2} y, - 3 x z, 3 x)

\frac{3}{( s + 1 ) ( s + 3 )}

\frac{18 + 12}{6 + 4}

d (u)^{2}

What is expand 7/((x^2-3x)^2) ?
The solution to expand 7/((x^2-3x)^2) is 7/(x^4-6x^3+9x^2)