What is expand ((2x-1)(3x-4))/(x^2+1) ?

The solution to expand ((2x-1)(3x-4))/(x^2+1) is (6x^2-11x+4)/(x^2+1)

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expand ((2x-1)(3x-4))/(x^2+1)

expand

\frac{( 2 x - 1 ) ( 3 x - 4 )}{x ^{2} + 1}

\frac{6 x ^{2} - 11 x + 4}{x ^{2} + 1}

Solution steps

\frac{( 2 x - 1 ) ( 3 x - 4 )}{x ^{2} + 1}

Expand

(2 x - 1) (3 x - 4) : 6 x^{2} - 11 x + 4

= \frac{6 x ^{2} - 11 x + 4}{x ^{2} + 1}

2 + 2 t + 6 + 6 t + 5 + 15 t

(\cdot + 5) (x + 3)

\frac{( 2 x + y ) + 5}{( 2 x + y ) ( 2 x - y )}

(1 + e^{- x}) (1 + e^{x})

\frac{3}{x ( x ^{2} + 3 )}

What is expand ((2x-1)(3x-4))/(x^2+1) ?
The solution to expand ((2x-1)(3x-4))/(x^2+1) is (6x^2-11x+4)/(x^2+1)