What is expand (n(n-1)(n+1))/3 ?

The solution to expand (n(n-1)(n+1))/3 is (n^3)/3-n/3

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expand (n(n-1)(n+1))/3

expand

\frac{n ( n - 1 ) ( n + 1 )}{3}

\frac{n ^{3}}{3} - \frac{n}{3}

Solution steps

\frac{n ( n - 1 ) ( n + 1 )}{3}

Expand

n (n - 1) (n + 1) : n^{3} - n

= \frac{n ^{3} - n}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{3} - n}{3} = \frac{n ^{3}}{3} - \frac{n}{3}

= \frac{n ^{3}}{3} - \frac{n}{3}

(x + h)^{(2)} - 3

\frac{n T}{s ( R ( M + n ^{2} J ) s + TB )}

10 x - (2 x + 9 = - 3 (15 - 4 x))

- \frac{4 ( 11 + 341 )}{11}

- 2 cos (0.5 (x - 7.3))

What is expand (n(n-1)(n+1))/3 ?
The solution to expand (n(n-1)(n+1))/3 is (n^3)/3-n/3