What is expand (g(4x+1))/(f(3x^2)) ?

The solution to expand (g(4x+1))/(f(3x^2)) is (4g)/(3xf)+g/(3x^2f)

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expand (g(4x+1))/(f(3x^2))

expand

\frac{g ( 4 x + 1 )}{f ( 3 x ^{2} )}

\frac{4 g}{3 x f} + \frac{g}{3 x ^{2} f}

Solution steps

\frac{g ( 4 x + 1 )}{f ( 3 x ^{2} )}

Remove parentheses:

(a) = a

= \frac{g ( 4 x + 1 )}{f \cdot 3 x ^{2}}

Expand

g (4 x + 1) : 4 gx + g

= \frac{4 gx + g}{3 x ^{2} f}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 gx + g}{f \cdot 3 x ^{2}} = \frac{4 gx}{f \cdot 3 x ^{2}} + \frac{g}{f \cdot 3 x ^{2}}

= \frac{4 gx}{3 x ^{2} f} + \frac{g}{3 x ^{2} f}

Cancel

\frac{4 gx}{f \cdot 3 x ^{2}} : \frac{4 g}{3 x f}

= \frac{4 g}{3 x f} + \frac{g}{3 x ^{2} f}

\frac{3 x ^{2}}{( 3 x ^{3} - 2 ) ^{3}}

(10 + 6.22 i) \cdot (10 + 9, 99 i)

\frac{n ( n - 1 )}{2}!

\frac{1}{( s + 2 ) ^{2} ( s - 2 )}

(x + 3) (x^{2} = 7 x + 1)

What is expand (g(4x+1))/(f(3x^2)) ?
The solution to expand (g(4x+1))/(f(3x^2)) is (4g)/(3xf)+g/(3x^2f)