What is expand ((3x+2y)^3)/(216) ?

The solution to expand ((3x+2y)^3)/(216) is (x^3)/8+(x^2y)/4+(xy^2)/6+(y^3)/(27)

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expand ((3x+2y)^3)/(216)

expand

\frac{( 3 x + 2 y ) ^{3}}{216}

\frac{x ^{3}}{8} + \frac{x ^{2} y}{4} + \frac{x y ^{2}}{6} + \frac{y ^{3}}{27}

Solution steps

\frac{( 3 x + 2 y ) ^{3}}{216}

(3 x + 2 y)^{3} = 27 x^{3} + 54 x^{2} y + 36 x y^{2} + 8 y^{3}

= \frac{27 x ^{3} + 54 x ^{2} y + 36 x y ^{2} + 8 y ^{3}}{216}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{3} + 54 x ^{2} y + 36 x y ^{2} + 8 y ^{3}}{216} = \frac{27 x ^{3}}{216} + \frac{54 x ^{2} y}{216} + \frac{36 x y ^{2}}{216} + \frac{8 y ^{3}}{216}

= \frac{27 x ^{3}}{216} + \frac{54 x ^{2} y}{216} + \frac{36 x y ^{2}}{216} + \frac{8 y ^{3}}{216}

\frac{27 x ^{3}}{216} = \frac{x ^{3}}{8}

\frac{54 x ^{2} y}{216} = \frac{x ^{2} y}{4}

\frac{36 x y ^{2}}{216} = \frac{x y ^{2}}{6}

\frac{8 y ^{3}}{216} = \frac{y ^{3}}{27}

= \frac{x ^{3}}{8} + \frac{x ^{2} y}{4} + \frac{x y ^{2}}{6} + \frac{y ^{3}}{27}

\frac{( - x + 10 ) \cdot ( x - 6 )}{2}

\frac{7 ( x + h ) + 8}{9 ( x + h ) - 7}

(ln (x) + 1)^{3}

\frac{k - s ^{2}}{s ^{2} ( s + a )}

2 (5 - 3 a) - 4 (a + 7 = 92)

What is expand ((3x+2y)^3)/(216) ?
The solution to expand ((3x+2y)^3)/(216) is (x^3)/8+(x^2y)/4+(xy^2)/6+(y^3)/(27)