What is expand ((3x-7)(x-4))/(4x-6) ?

The solution to expand ((3x-7)(x-4))/(4x-6) is (3x^2-19x+28)/(4x-6)

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expand ((3x-7)(x-4))/(4x-6)

expand

\frac{( 3 x - 7 ) ( x - 4 )}{4 x - 6}

\frac{3 x ^{2} - 19 x + 28}{4 x - 6}

Solution steps

\frac{( 3 x - 7 ) ( x - 4 )}{4 x - 6}

Expand

(3 x - 7) (x - 4) : 3 x^{2} - 19 x + 28

= \frac{3 x ^{2} - 19 x + 28}{4 x - 6}

(x y + 1) d y

\frac{k}{s ( j s + 1 )}

(2 x^{3} - 2 x + 1) \circ (3 x)

\frac{( - 1 ) ^{n} + 1}{n}

4 (2 x + 3 = - 12)

What is expand ((3x-7)(x-4))/(4x-6) ?
The solution to expand ((3x-7)(x-4))/(4x-6) is (3x^2-19x+28)/(4x-6)