en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d/(dq)((C)(7+2q-3q^2))

Solution

\frac{d}{d q} ((C) (7 + 2 q - 3 q^{2}))

Solution

C (- 6 q + 2)

Solution steps

\frac{d}{d q} ((C) (7 + 2 q - 3 q^{2}))

Treat

C

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= C \frac{d}{d q} (7 + 2 q - 3 q^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= C (\frac{d}{d q} (7) + \frac{d}{d q} (2 q) - \frac{d}{d q} (3 q^{2}))

\frac{d}{d q} (7) = 0

\frac{d}{d q} (2 q) = 2

\frac{d}{d q} (3 q^{2}) = 6 q

= C (0 + 2 - 6 q)

Simplify

= C (- 6 q + 2)

Popular Examples

expand x/((x-3)(x+1))expand

\frac{x}{( x - 3 ) ( x + 1 )}

expand-(5(y-1))/(13(y+1))expand

- \frac{5 ( y - 1 )}{13 ( y + 1 )}

expand f(f(f(-2.8)+3,5)-1)expand

f (f (f (- 2.8) + 3, 5) - 1)

expand e^{-x^2}(1+2x)-x expand

e^{- x^{2}} (1 + 2 x) - x

expand (1+3t)t^2dt expand

(1 + 3 t) t^{2} d t

Frequently Asked Questions (FAQ)

What is the d/(dq)((C)(7+2q-3q^2)) ?
The d/(dq)((C)(7+2q-3q^2)) is C(-6q+2)
What is the first d/(dq)((C)(7+2q-3q^2)) ?
The first d/(dq)((C)(7+2q-3q^2)) is C(-6q+2)