What is expand (x+1)/((x+2)(x^2-x-3)) ?

The solution to expand (x+1)/((x+2)(x^2-x-3)) is (x+1)/(x^3+x^2-5x-6)

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expand (x+1)/((x+2)(x^2-x-3))

expand

\frac{x + 1}{( x + 2 ) ( x ^{2} - x - 3 )}

\frac{x + 1}{x ^{3} + x ^{2} - 5 x - 6}

Solution steps

\frac{x + 1}{( x + 2 ) ( x ^{2} - x - 3 )}

Expand

(x + 2) (x^{2} - x - 3) : x^{3} + x^{2} - 5 x - 6

= \frac{x + 1}{x ^{3} + x ^{2} - 5 x - 6}

(1 + x^{2} + y^{2} + x^{2} y^{2}) d y

\frac{x - 7}{( x + 1 ) ( x - 2 )}

\frac{( y + z ) ^{2} - 4}{y}

sin ((x + y) sin (x - y))

\frac{2 x + 3}{( x + 1 ) ( x + 2 )}

What is expand (x+1)/((x+2)(x^2-x-3)) ?
The solution to expand (x+1)/((x+2)(x^2-x-3)) is (x+1)/(x^3+x^2-5x-6)