What is the d/(dt)((x)t(2t+1)^2) ?

The d/(dt)((x)t(2t+1)^2) is (dx)/(dt)t(2t+1)^2+(12t^2+8t+1)x

What is the first d/(dt)((x)t(2t+1)^2) ?

The first d/(dt)((x)t(2t+1)^2) is (dx)/(dt)t(2t+1)^2+(12t^2+8t+1)x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((x) t (2 t + 1)^{2})

\frac{d x}{d t} t (2 t + 1)^{2} + (12 t^{2} + 8 t + 1) x

Solution steps

\frac{d}{d t} ((x) t (2 t + 1)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = t (2 t + 1)^{2}

= \frac{d x}{d t} t (2 t + 1)^{2} + \frac{d}{d t} (t (2 t + 1)^{2}) x

\frac{d}{d t} (t (2 t + 1)^{2}) = 12 t^{2} + 8 t + 1

= \frac{d x}{d t} t (2 t + 1)^{2} + (12 t^{2} + 8 t + 1) x

\frac{10 ( 4 23 - 5 )}{49}

\frac{d}{d v} ((x) (u^{2} v + v))

(x, y) (x + 2 y - 3)

- 5 (x + 7 y = 6)

\frac{99.6 ( s + 0.5 ) ^{2}}{s}

What is the d/(dt)((x)t(2t+1)^2) ?
The d/(dt)((x)t(2t+1)^2) is (dx)/(dt)t(2t+1)^2+(12t^2+8t+1)x
What is the first d/(dt)((x)t(2t+1)^2) ?
The first d/(dt)((x)t(2t+1)^2) is (dx)/(dt)t(2t+1)^2+(12t^2+8t+1)x