What is expand 4/((x^2+4)(x-2)) ?

The solution to expand 4/((x^2+4)(x-2)) is 4/(x^3-2x^2+4x-8)

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expand 4/((x^2+4)(x-2))

expand

\frac{4}{( x ^{2} + 4 ) ( x - 2 )}

\frac{4}{x ^{3} - 2 x ^{2} + 4 x - 8}

Solution steps

\frac{4}{( x ^{2} + 4 ) ( x - 2 )}

Expand

(x^{2} + 4) (x - 2) : x^{3} - 2 x^{2} + 4 x - 8

= \frac{4}{x ^{3} - 2 x ^{2} + 4 x - 8}

\frac{t ( 2 v - a t )}{2}

6 (- 13)

(1, 5 m + 2, n + 5 p) - (- 2, 3 m - 3.2 p + 12 n)

\frac{( y - 1 ) ^{2}}{y}

\frac{4}{( x - 1 ) ^{2}}

What is expand 4/((x^2+4)(x-2)) ?
The solution to expand 4/((x^2+4)(x-2)) is 4/(x^3-2x^2+4x-8)