What is expand 2h(x)-(6x-1-5=-1) ?

The solution to expand 2h(x)-(6x-1-5=-1) is -6x+2h(x)+6=1

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expand 2h(x)-(6x-1-5=-1)

expand

2 h (x) - (6 x - 1 - 5 = - 1)

- 6 x + 2 h (x) + 6 = 1

Solution steps

2 h (x) - (6 x - 1 - 5 = - 1)

- (6 x - 1 - 5 = - 1) : - 6 x + 1 + 5 = 1

2 h (x) - 6 x + 1 + 5 = 1

Expand

2 h (x) - 6 x + 1 + 5 : - 6 x + 2 h (x) + 6

- 6 x + 2 h (x) + 6 = 1

2 (e^{x} - e^{- x}) (e^{x} + e^{- x})

\frac{3 ( 5 x - 6 )}{2}

\frac{10}{( s + 1 ) ( s + 2 )}

(2 x - ux) u d x + x d u

\frac{( 4 h + 3 k - 4 ) ^{2}}{25}

What is expand 2h(x)-(6x-1-5=-1) ?
The solution to expand 2h(x)-(6x-1-5=-1) is -6x+2h(x)+6=1